2011 CSC Placement Paper - INoida - Delhi/NCR

  • CategoryIT
  • Sub CategoryPlacement Papers
  • LocationNoida - Delhi/NCR
  • CompanyCSC
  • Posted date on our Website10 February 2011

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2011 CSC Placement Paper:-


1.------- is associated with webservices.

a) WSDL b) WML c) web sphere d) web logic

2.any large single block of data stored in a database, such as a picture or sound file, which does not include record fields, and cannot be directly searched by the database’s search engine.

a) TABLE b) BLOB c) VIEW d) SCHEME

3.Areserved area of the immediate access memeory used to increase the running speed of the computer program.

a) session memory b) bubble memory c) cache memory d) shared memory

4.a small subnet that sit between atrusted internal network and an untruster external network, such as the public internet.

a) LAN b) MAN c) WAN d) DMZ

5.technologies that use radio waves to automatically identify people or objects,which is very similar to the barcode identification systems,seen in retail stores everyday.

a)BLUETOOTH b) RADAR c)RSA SECURE ID d)RFID

6.main(){
float fl = 10.5;
double dbl = 10.5
if(fl ==dbl)
printf(“UNITED WE STAND”);
else
printf(“DIVIDE AND RULE”)
}
what is the output?

a)compilation error b)UNITED WE STAND c)DIVIDE AND RULE d)linkage error.

7.main(){
static int ivar = 5;
printf(“%d”,ivar--);
if(ivar)
main();
}

what is the output?

a)1 2 3 4 5 b) 5 4 3 2 1 c)5 d)compiler error:main cannot be recursive function.

8.main()
{
extern int iExtern;
iExtern = 20;
printf(“%d”,iExtern);
}
what is the output?

a)2 b) 20 c)compile error d)linker error

9..#define clrscr() 100
main(){
clrscr();
printf(“%d\n\t”, clrscr());
}
what is the output?

a)100 b)10 c)compiler errord)linkage error

10.main()
{
void vpointer;
char cHar = ‘g’, *cHarpointer = “GOOGLE”;
int j = 40;
vpointer = &cHar;
printf(“%c”,*(char*)vpointer);
vpointer = &j;
printf(“%d”,*(int *)vpointer);
vpointer = cHarpointer;
printf(“%s”,(char*)vpointer +3);
}
what is the output?

a)g40GLE b)g40GOOGLE c)g0GLE d)g4GOO

11.#define FALSE -1
#define TRUE 1
#define NULL 0
main() {
if(NULL)
puts(“NULL”);
else if(FALSE)
puts(“TRUE”);
else
puts(“FALSE”);
}
what is the output?

a)NULL b)TRUE c)FALSE d)0

12.main() {
int i =5,j= 6, z;
printf(“%d”,i+++j);
}
what is the output?
a)13 b)12 c)11 d)compiler error

13.main() {
int i ;
i = accumulator();
printf(“%d”,i);
}
accumulator(){
_AX =1000;
}
what is output?

a)1 b)10 c)100 d)1000

14.main() {
int i =0;
while(+(+i--)!= 0)
i- = i++;
printf(“%d”,i);
}
what is the output?
a)-1 b)0 c)1 d)will go in an infinite loop

15.main(){
int i =3;
for(; i++=0;)
printf((“%d”,i);
}
what is the output?

a)1b)2c)1 2 3d)compiler error:L value required.

16.main(){
int i = 10, j =20;
j = i ,j?(i,j)?i :j:j;
printf(“%d%d”,i,j);
}what is the output?
a)20 b)20 c)10 d)10

17.main(){
extern i;
printf(“%d\t”,i);{
int i =20;
printf(“%d\t”,i);
}
}
what is output?

a) “Extern valueof i “ 20 b)Externvalue of i”c)20d)linker Error:unresolved external symbol i

18.int DIMension(int array[]){
return sizeof(array/sizeof(int);}
main(){
int arr[10];
printf(“Array dimension is %d”,DIMension(arr));
}
what is output?

a)array dimension is 10 b)array dimension is 1
c) array dimension is 2 d)array dimension is 5

19.main(){
void swap();
int x = 45, y = 15;
swap(&x,&y);
printf(“x = %d y=%d”x,y);
}
void swap(int *a, int *b){
*a^=*b, *b^=*a, *a^ = *b;
what is the output?

a) x = 15, y =45 b)x =15, y =15 c)x =45 ,y =15 d)x =45 y = 45

20.main(){
int i =257;
int *iptr =&i;
printf(“%d%d”,*((char*)iptr),*((char *)iptr+1));
}
what is output?
a)1, 257 b)257 1c)0 0d)1 1

21.main(){
int i =300;
char *ptr = &i;
*++ptr=2;
printf(“%d”,i);
}
what is output?

a)556 b)300 c)2 d)302

22.#include
main(){
char *str =”yahoo”;
char *ptr =str;
char least =127;
while(*ptr++)
least = (*ptr
printf(“%d”,least);
}
what is the output?

a)0 b)127 c)yahoo d)y

23.Declare an array of M pointers to functions returing pointers to functions returing pointers to characters.
a)(*ptr[M]()(char*(*)()); b)(char*(*)())(*ptr[M])()
c)(char*(*)(*ptr[M]())(*ptr[M]() d)(char*(*)(char*()))(*ptr[M])();

24.void main(){
int I =10, j=2;
int *ip = &I ,*jp =&j;
int k = *ip/*jp;
printf(“%d”,k);
}
what is the output?

a)2 b)5 c)10 d)compile error:unexpected end of file in comment started in line 4

25.main(){
char a[4] =”GOOGLE”;
printf(“%s”,a);
}
what is the output?

a)2 b) GOOGLE c) compile error: yoo mant initializers d) linkage error.

26.For 1MB memory, the number of address lines required

a)12 b)16 c)20 d)32

27.There is a circuit using 3 nand gates with 2 inputes and 1 output,f ind the output.

a) AND b) OR c) XOR d) NAND

28.what is done for push operation

a) SP is incremented and then the value is stored.
b) PC is incremented and then the value is stored.
c) PC is decremented and then the value is stored.
d) SP is decremented and then the value is stored.

29.Memory allocation of variables declared in a program is ------

a) Allocated in RAM
b) Allocated in ROM
c) Allocated in stack
d) Assigned in registers.

30.What action is taken when the processer under execution is interrupted by TRAP in 8085MPU?

a) Processor serves the interrupt request after completing the execution of the current instruction.
b) processer serves the interrupt request after completing the current task.
c) processor serves the interrupt immediately.
d) processor serving the interrupt request depent deprnds upon the priority of the current task under execution.

31.purpose of PC (program counter)in a microprocessor is ----

a) To store address of TOS(top of stack)
b) To store address of next instructions to be executed
c) count the number of instructions
d) to store the base address of the stack.

32.conditional results after execution of an instruction in a microprocess is stored in

a) register b) accumulator c) flag register d) flag register part of PSW (program status word)

33.The OR gate can be converted to the NAND function by adding----gate(s)to the input of the OR gate.

a) NOT b) AND c) NOR d) XOR

34.In 8051microcontroller ,------has a dual function.

a) port 3 b) port 2 c) port 1 d) port 0

35.An 8085 based microprocessor with 2MHz clock frequency,will execute the following chunk of code with how much delay?
MVI B,38H
HAPPY: MVI C, FFH
SADDY: DCR C
JNZ SADDY
DCR B
JNC HAPPY

a) 102.3 b)114.5 c)100.5 d)120

36.In 8085 MPU what will be the status of the flag after the execution of the following chunk of code.

MVI B,FFH
MOV A,B
CMA
HLT

a)S = 1, Z = 0, CY = 1 b)S = 0, Z = 1, CY = 0
c) S = 1, Z = 0, CY = 0 d)S = 1, Z = 1 ,CY = 1

37.A positive going pulse which is always generated when 8085 MPU begins the machine cycle.

a) RD b) ALE c) WR d) HOLD

38.when a ----- instruction of 8085 MPU is fetched , its second and third bytes are placed in the W and Z registers.

a) JMP b) STA c) CALL d) XCHG

39.what is defined as one subdivision of the operation performed in one clock period.

a) T- State b) Instruction Cycle c) Machine Cycle d) All of the above

40.At the end of the following code, what is the status of the flags.
LXI B, AEC4H
MOV A,C
ADD B
HLT

a) S = 1, CY = 0, P = 0 , AC = 1 b) S =0 , CY = 1, P = 0,AC = 1
c) S = 0, CY = 1, P = 0 , AC = 1 d) S = 0, CY = 1, P = 1 , AC = 1

About CSC:-

CSC was established in 1959. CSC developed smart, technology-enabled solutions to solve our clients' toughest challenges, demonstrating a commitment to excellence and a passion for exceeding expectations. CSC senior management team has an average of 25 years of domestic and international IT experience and a strong history of business, academic and technological accomplishments.

CSC (NYSE: CSC) reported trailing 12 months revenue of $16.2 billion for the third quarter ending December 31, 2010.

Why CSC - Why should i join CSC?:-


The Brand CSC:- The legendary CSC story only grows richer with age.

Great Work Culture:- CSC’s supportive work culture brings out the best in you.

Excellent People Practices:- When you join CSC, you become part of a caring family.

Dynamic Growth and Learning:- You’ll find opportunities to grow and learn all around you at CSC.

Embracing Diversity:- CSC has a strong commitment to supporting diversity of all kinds.

Social Responsibility:- Our Corporate Social Responsibility Committee undertakes many important community activities.

Reputation:- Experience the joy of working for one of the best companies in the industry.

Contact Details:

Address of CSC:-

Noida:-

DLF IT Park, A-44/45,
Sector 62,
Noida (UP) - 201 301
Ph: +91-120-6600666 / 4430666
   
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Unit no 301, 'A' wing,
Kensington IT/ITES SEZ,
Hiranandani business park,
Powai,
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Ph: +91-22-66045000/ 25710600
   
 
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Fax:+91-40-44307777
 
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Fax:+91-80-25358502

http://www.csc.com/careersin/flx/16394-job_opportunities

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Comments / Reviews / Queries On

  • Pls provide the answers Saravaba kumar, on 22-09-2011 Report Abuse

  • plz give complete solution along with question divay, on 27-07-2011 Report Abuse

  • i got the 2011 placement papers bt pls send me the answers samidha, on 27-02-2011 Report Abuse
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